c^2-19c+48=

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Solution for c^2-19c+48= equation:


Simplifying
c2 + -19c + 48 = 0

Reorder the terms:
48 + -19c + c2 = 0

Solving
48 + -19c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(3 + -1c)(16 + -1c) = 0

Subproblem 1

Set the factor '(3 + -1c)' equal to zero and attempt to solve: Simplifying 3 + -1c = 0 Solving 3 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1c = 0 + -3 -1c = 0 + -3 Combine like terms: 0 + -3 = -3 -1c = -3 Divide each side by '-1'. c = 3 Simplifying c = 3

Subproblem 2

Set the factor '(16 + -1c)' equal to zero and attempt to solve: Simplifying 16 + -1c = 0 Solving 16 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + -1c = 0 + -16 Combine like terms: 16 + -16 = 0 0 + -1c = 0 + -16 -1c = 0 + -16 Combine like terms: 0 + -16 = -16 -1c = -16 Divide each side by '-1'. c = 16 Simplifying c = 16

Solution

c = {3, 16}

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